5 Most Important Questions with Short Tricks on Mixture & Alligation Question 1: In a mixture of 75 litres, the ratio of milk to w...
5 Most Important Questions with Short Tricks on Mixture & Alligation
Question 1: In a mixture of 75 litres, the ratio of milk to water is 2 : 1. The amount of water to be further added to the mixture so as to make the ratio of the milk to water 1 : 2 will be
(1) 45 litres
(2) 60 litres
(3) 75 litres
(4) 80 litres
Solution:
In 75 litres of the mixture.
Let x litres of water be added,
Short Trick:
3 units = 75 l because 75 l was in ratio 2 : 1 initially.
Question 2: A mixture of 40 litres of milk and water contains 10% water. How much water must be added to make 20% water in the new mixture?
(1) 3 litres
(2) 4 litres
(3) 5 litres
(4) 6 litres
Solution
(8 x 5 = 40 l which is the initial quantity. Hence 1 is also multiplied by 5)
Short Trick:
(40 + x) x 20% = 4 + x
x = 5l
Question 3: In three vessels each of 10 l capacity, mixture of milk and water is filled, the ratios of milk and water are 2 : 1, 3 : 1 and 3 : 2 in the three respective vessels, if all the three vessels are emptied into a single large vessel, find the proportion of milk and water in the mixture.
(1) 121 : 59
(2) 123 : 59
(3) 125 : 59
(4) 127 : 59
Solution:
2nd Method :
L.C.M. of 3, 4 & 5. Hence 3 is multiplied by 4 x 5; 4 is multiplied by 3 x 5; 5 is multiplied by 3 x 4.
Question 4: Vessels A and B contain mixtures of milk and water in the ratios 4 : 5 and 5 : 1 respectively. In what ratio should quantities of mixture be taken from A and B to form a mixture in which milk and water is in the ratio 5 : 4?
(1) 2 : 5
(2) 4 : 3
(3) 5 : 2
(4) 2 : 3
Solution:
Quantity of milk in vessel A
Quantity of milk in vessel B
Quantity of milk in final mixture
So, mixture of vessels A and B are mixed in ratio of 5 : 2.
2nd Method :
Question 5: 50 g of an alloy of gold and silver contains 80% gold (by weight). The quantity of gold, that is to be mixed up with this alloy, so that it may contain 95% gold, is
(1) 200 g
(2) 150 g
(3) 50 g
(4) 10 g
Solution:
Quantity of gold in the alloy
Let x gm of gold is added, then
Other Method:
1 unit when multiplied by 50 gives 50g. Hence 3 unit is also multiplied by 50.
For Formule click here
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